Question 929930: Solve the problem. In one U.S. city, the quadratic function f(x)= 0.039x^2-0.48x+36.66 models the average age y, at which men were the first married x years after 1900. In which year was this average age at a minimum? (Round to the nearest year.) What was the average age that men were first married that year? (Round to the nearest tenth.)
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! f(x)= 0.039x^2 - 0.48x + 36.66 = 0
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the above quadratic equation is in standard form, with a=0.039, b=-0.48 and c=36.66
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
0.039 -0.48 36.66
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has a minimum at:
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( 6.15384615, 35.1830769 )
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answer:
the minimum occurred in the year 1900 + 6.15384615 = 1906
the average age that men were first married that year = 35.2
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