Question 926788: a boy is 10 years older than his brother. in four years, he will be twice as old as his brother. find the present age of each Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = boy age
y = brother age
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x = y + 10
x + 4 = 2(y + 4)
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put the system of linear equations into standard form
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x - y = 10
x + 4 = 2y + 8
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x - y = 10
x - 2y = 4
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solution:
x = boy age = 16
y = brother age = 6
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