Question 924468: 2 brothers have a combined age of 42 years. Steve is twice as old as Bob was when Steve was as old as Bob is now. How old are they? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = steve's age now
y = bob's age now
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x + y = 42
x = 2(y - (x - y))
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put the system of linear equations into standard form
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x + y = 42
x = 2(y - x + y)
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x + y = 42
x = 2(2y - x)
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x + y = 42
x = 4y - 2x
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x + y = 42
3x - 4y = 0
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = steve's age now = 24
y = bob's age now = 18
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