SOLUTION: I am having trouble figuring out how to set up this problem. Thank you in advance to anyone who helps! Addison is 3 times as old as Bailey and Bailey is 2.5 times as old as Chris

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Question 905890: I am having trouble figuring out how to set up this problem. Thank you in advance to anyone who helps!
Addison is 3 times as old as Bailey and Bailey is 2.5 times as old as Christopher. If the sum off all of their ages is 66, how old is Christopher?
Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x Christopher's age
Addison + Bailey + Christopher
3(2.5x) + (2.5x) + x = 66
7.5x + 2.5x + x = 66
11x = 66
x = 6, Christopher's age, Bailey is 15 and Addison is 45
And...
sum = 66

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A=3B
B=%285%2F2%29C
A%2BB%2BC=66
From eq. 2,
C=%282%2F5%29B
Substitute,
3B%2BB%2B%282%2F5%29B=66
%2815%2F5%2B5%2F5%2B2%2F5%29B=66
%2822%2F5%29B=66
B=15
Now that you know Bailey's age, work backwards to find Addison and Christopher's ages.