SOLUTION: The sum of 4 times Joan's age and 5 times Larry's age is 37. Larry is 1 year less than twice as old as Joan. What are their ages?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: The sum of 4 times Joan's age and 5 times Larry's age is 37. Larry is 1 year less than twice as old as Joan. What are their ages?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 901859: The sum of 4 times Joan's age and 5 times Larry's age is 37. Larry is 1 year less than twice as old as Joan. What are their ages?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
4J + 5(2J-1) = 37
14J = 42
J = 3, Joan's age. Larry is 5. 2%2A3-1
And...
12 + 25 = 37