SOLUTION: Five years ago, a mother was twice as old as her son. In 6years time,the sum of their ages will be 82. Find their present ages

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Question 895303: Five years ago, a mother was twice as old as her son. In 6years time,the sum of their ages will be 82. Find their present ages
Answer by mark_henrhiz(40) About Me  (Show Source):
You can put this solution on YOUR website!
x-5+=+2%28y-5%29
x%2B6+%2B+y%2B6+=+82
x-5+=+2y-10
x-2y+=+-10%2B5
x-2y+=+-5
x%2By+=+82-12
x%2By+=+70
x-2y+=+-5
x%2By+=+70 then you solve it either through substitution method or
addition method