Question 894005: Johns mother is 8 more than twice his age. His father is three years older than his mother is. If the three family members have lived a total of 94 years, how old is each family member?
I've tried 94= m(8+2x) + 3f + j
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website!  , Johns mother is 8 more than twice his age;
 , His father is three years older than his mother is.;
 , the three family members have lived a total of 94 years.
That is a system of three linear equations in three unknown variables. Handle the solution any way you want: Substitution, Elimination, or Matrix Operations.
Using matrix row operations, I found f=36, j=25, m=33
Starting matrix in form f,j,m,C:
Final matrix after the row operations :
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Johns mother is 8 more than twice his age. His father is three years older than his mother is. If the three family members have lived a total of 94 years, how old is each family member?
I've tried 94= m(8+2x) + 3f + j
Let John's age be J
Then Mom's is: 2J + 8
Dad's: 2J + 8 + 3, or 2J + 11
Therefore, J + 2J + 8 + 2J + 11 = 94
5J = 94 - 19
5J = 75
J, or John's current age is:  , or 
You should be able to find Mom's and Dad's!!
Then do a check!!
If you need a complete and detailed solution, let me know!!
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