Question 890321: Before 3 years father age was 7 times of sons age after 3years father age will be 4 times of sons age calculate the present age sons and father
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! let f = father's age
let s = son's age
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Write an equation for each statement, simplify
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Before 3 years father age was 7 times of sons
f - 3 = 7(s-3)
f - 3 = 7s - 21
f = 7s - 21 + 3
f = 7s - 18
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after 3years father age will be 4 times of sons
f + 3 = 4(s+3)
f + 3 = 4s + 12
f = 4s + 12 - 3
f = 4s + 9
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f=f, so we can write this
7s - 18 = 4s + 9
7s - 4s = 9 + 18
3s = 27
s = 27/3
s = 9 yrs is the son
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You can use f = 4s + 9, to find the father's age
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Check your solutions in both statements.
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