SOLUTION: Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of the man and his son

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Question 888290: Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of the man and his son
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +m+ = man's age now
Let +s+ = son's age now
-------------------------
(1) +m+-+2+=+5%2A%28+s+-+2+%29+
(2) +m+%2B+2+=+3%2A%28+s+%2B+2+%29+%2B+8+
-----------------------------
(1) +m+-+2+=+5s+-+10+
(1) +5s+-+m+=+8+
and
(2) +m+%2B+2+=+3s+%2B+6+%2B+8+
(2) +-3s+%2B+m+=+12+
----------------------
Add (1) and (2)
(1) +5s+-+m+=+8+
(2) +-3s+%2B+m+=+12+
+2s+=+20+
+s+=+10+
and
(1) +5s+-+m+=+8+
(1) +5%2A10+-+m+=+8+
(1) +m+=+50+-+8+
(1) +m+=+42+
The son is 10
The man is 42
check:
(2) +m+%2B+2+=+3%2A%28+s+%2B+2+%29+%2B+8+
(2) +42+%2B+2+=+3%2A%28+10+%2B+2+%29+%2B+8+
(2) +44+=+3%2A12+%2B+8+
(2) +44+=+36+%2B+8+
(2) +44+=+44+
OK