SOLUTION: "Eight is my lucky number. Eight years ago I was eight times the age of my son. Today the sum of our ages is 52 - you tell me how old I am."

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Question 885181: "Eight is my lucky number. Eight years ago I was eight times the
age of my son. Today the sum of our ages is 52 - you tell me how old I am."

Found 2 solutions by KMST, MathTherapy:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
n= age of the son 8 years ago.
8n= age of the father 8 years ago.
n%2B8= age of the son now.
8n%2B8= age of the father now.
%288n%2B8%29%2B%28n%2B8%29=52= sum of father and son's ages now.

%288n%2B8%29%2B%28n%2B8%29=52-->8n%2B8%2Bn%2B8=52-->8n%2Bn%2B8%2B8=52-->9n%2B16=52-->9n=52-16-->9n=36-->n=36%2F9-->n=4
The father's age now is 8n%2B8=8%2A4%2B8=32%2B8=highlight%2840%29 .

Verification:
The son's age now is 4%2B8=12 ,
and the sum of their ages is 40%2B12=52 .

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
"Eight is my lucky number. Eight years ago I was eight times the
age of my son. Today the sum of our ages is 52 - you tell me how old I am." 


Let mine and my son's current ages be M, and S, respectively

Then we can say that: M - 8 = 8(S - 8)_____M - 8 = 8S - 64

M - 8S = - 64 + 8____M - 8S = - 56 ------ eq (i)

Also, M + S = 52_______S = 52 - M ------- eq (ii)



M - 8S = - 56 ------ eq (i)

M - 8(52 - M) = - 56 ------- Substituting 52 - M for S in eq (i)

M - 416 + 8M = - 56

9M = - 56 + 416

9M = 360

M, or my age = highlight_green%28highlight_green%2840%29%29