SOLUTION: A FATHER IS 3 TIMES AS OLD AS HIS SON. AFTER 12 YEARS HIS AGE WILL BE TWICE AS THAT OF HIS SON THEN FIND THE PRESENT AGES

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Question 884821: A FATHER IS 3 TIMES AS OLD AS HIS SON. AFTER 12 YEARS HIS AGE WILL BE TWICE AS THAT OF HIS SON THEN FIND THE PRESENT AGES
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
F = 3S
F+12 = 2(S+12)
Substitute the value of F from the first equation into the second.
(3S) + 12 = 2S + 24
Subtract 2S from each side
S + 12 = 24
Subtract 12 from each side
S = 12
.
If the son is 12, then the father is 36.
In 12 years, the son will be 24 and the father 48.