SOLUTION: The decay of 457mg of an isotope is given by A(t)=457e^-0.019t, where t is time in years. Find the amount left after 78 years.

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Question 881789: The decay of 457mg of an isotope is given by A(t)=457e^-0.019t, where t is time in years. Find the amount left after 78 years.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+A%28t%29+=+457%2Ae%5E%28-.019t%29+
Find +A%2878%29+
+A%2878%29+=+457%2Ae%5E%28-.019%2A78%29+
+A%2878%29+=+457%2Ae%5E%28-1.482%29+
+A%2878%29+=+457%2A.22718+
+A%2878%29+=+103.82+
103.82 mg are left after 78 years