SOLUTION: Norman is 4 times as old his brother Nicholas. Their combined age is 15. How old is each boy?

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Question 874582: Norman is 4 times as old his brother Nicholas. Their combined age is 15. How old is each boy?



Answer by mxgirl22(39) About Me  (Show Source):
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Norman is 4 times as old his brother Nicholas. Their combined age is 15. How old is each boy?
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Step 1.) Label

Let Norman: N (Note: Norman is capital N)

Let Nicholas: n (Note: Nicholas is lower case n)

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Step 2.) Look for keywords.
Norman is(=) 4 times(4x) as old his brother Nicholas(n).
Their combined(+) age is(=) 15.

Norman=4%2An
Nicholas=n
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Step 3.) Using the information we got in step 2, set up the equation.

%284%2An%29%2Bn=15

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Step 4.) Solve for "n" (Nicholas's age)

%284%2An%29%2Bn=15
4n%2Bn=15
5n=15
5n%2F5=15%2F5
n=3
Nicholas is 3 years old.
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Step 5.) Now that we know Nicholas's age, we can find Norman's age.

Using the answer in step 4) we know n=3

In step 2) we found out that Norman's age is: N=4%2An

So now plug in n=3 into the equation to solve for Norman's age.

N=4%2An

N=4%2A%283%29

N=12

Norman is 12 years old.

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Step 6.) Check.

Remember,

Let Norman: N (Note: Norman is capital N)


Let Nicholas: n (Note: Nicholas is lower case n)

N%2Bn=15

12%2B3=15

15=15

Checks!
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Step 7.) Answer.

Norman is 12 years old and Nicholas is 3 years old.