SOLUTION: 1 year ago a mother was four times older than her son. after 6 years her age become more than double her sons age by 5 years. what will be the ratio of their present age? plz

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Question 866725: 1 year ago a mother was four times older than her son. after 6 years her age become more than double her sons age by 5 years. what will be the ratio of their present age?

plz answer this question...
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +m+ = mother's age now
Let +s+ = son's age now
+m+-+1+ = mother's age 1 year ago
+s+-+1+ = son's age 1 year ago
+m+%2B+6+ = mother's age in 6 years
+s+%2B+6+ = son's age in 6 years
------------------------------------------
(1) +m+-+1+=+4%2A%28+s+-+1+%29+
(2) +m+%2B+6+=+2%2A%28+s+%2B+6+%29+%2B+5+
------------------------------------
(1) +m+-+1+=+4s+-+4+
(1) +4s+-+m+=+3+
and
(2) +m+%2B+6+=+2s+%2B+12+%2B+5+
(2) +m+%2B+6+=+2s+%2B+17+
(2) +-2s+%2B+m+=+11+
----------------------------
Add (1) and (2)
(2) +-2s+%2B+m+=+11+
(1) +4s+-+m+=+3+
+2s+=+14+
+s+=+7+
and, since
(1) +m+-+1+=+4%2A%28+s+-+1+%29+
(1) +m+-+1+=+4%2A%28+7+-+1+%29+
(1) +m+-+1+=+24+
(1) +m+=+25+
-----------------------
The mother is 25
The son is 7
-------------
check:
(2) +m+%2B+6+=+2%2A%28+s+%2B+6+%29+%2B+5+
(2) +25+%2B+6+=+2%2A%28+7+%2B+6+%29+%2B+5+
(2) +31+=+2%2A13+%2B+5+
(2) +31+=+26+%2B+5+
(2) +31+=+31+
and
(1) +m+-+1+=+4%2A%28+s+-+1+%29+
(1) +25+-+1+=+4%2A%28+7+-+1+%29+
(1) +24+=+4%2A6+
(1) +24+=+24+
OK

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The other tutor's solution is probably the one expected, but,
4 times older = 5 times as old.
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Is 1 time older the same age?
4 times older = a 400% increase in age = 5 times as old.
Be careful of that.
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PS A thing can't be 10 times smaller, since 1 time smaller is zero.
This is what's known as GIBBERISH.