SOLUTION: Yesterday one kitten was 4 times the age of another kitten. Today the sum of their ages is 10 days. How old are the two kittens today?

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Question 859986: Yesterday one kitten was 4 times the age of another kitten. Today the sum of their ages is 10 days. How old are the two kittens today?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let their ages today be +a+ and +b+ days
Let +a+ be the older kitten
--------------------------
Yesterday their ages were +a+-+1+ days
and +b+-+1+ days
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(1) +a+-+1+=+4%2A%28+b+-+1+%29+
(2) +a+%2B+b+=+10+
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(1) +a+-+1+=+4b+-+4+
(1) +-a+%2B+4b+=+3+
Add equations (1) and (2)
(1) +-a+%2B+4b+=+3+
(2) +a+%2B+b+=+10+
+5b+=+13+
+b+=+13%2F5+
and
(2) +a+%2B+13%2F5+=+10+
(2) +a+=+50%2F5+-+13%2F5+
(2) +a+=+37%2F5+
------------------
Their ages are 7.4 days and 2.6 days
check:
(1) +a+-+1+=+4%2A%28+b+-+1+%29+
(1) +37%2F5+-+1+=+4%2A%28+13%2F5+-+1+%29+
(1) +32%2F5+=+4%2A%28+8%2F5+%29+
(1) +32%2F5+=+32%2F5+
OK