SOLUTION: Find the area of a circle in which a chord AB is 48cm and the perpendicular bisector of the chord, originating at the centre of the circle, is 10cm.
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Question 847874: Find the area of a circle in which a chord AB is 48cm and the perpendicular bisector of the chord, originating at the centre of the circle, is 10cm. Answer by hamsanash1981@gmail.com(151) (Show Source):
You can put this solution on YOUR website! Let the center of the circle be O and O be the point at which it bisects the chord AB such that OPA forms the right angled triangle and OA is radius of the circle then OP = 10cm and AP = 24
By Pythagoras theorem,
OA = 26
RADIUS = 26
AREA = 22/7*26*26
=2124.57 Sq cm
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