SOLUTION: a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older tha

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Question 835040: a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older than combined ages of kids what is the mans age

Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older than combined ages of kids what is the mans age
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Equations:
s = d + 3
f+1 = 6d
f+10 = (s+10) + (d+10) + 14
----
f+10 = (d+13) + d+10 + 14
f = 2d +13+14
f = 2d + 27
----
f+1 = 2d + 28
6d = 2d + 28
4d = 28
daughter = 7 yrs (now)
----
son = d+3 = 10 yrs (now)
father = 6d-1 = 41 yrs
===============================
Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +f+ = father's's age now
Let +s+ = son's age now
Let +d+ = daughter's age now
----------------------------
(1) +s+=+d+%2B+3+
(2) +f+%2B+1+=+6d+
(3) +f+%2B+10+=+%28+s%2B10+%29+%2B+%28+d%2B10+%29+%2B+14+
--------------------------------------
(2) +f+=+6d+-+1+
and
(3) +f+%2B+10+=++s%2B10+%2B++d%2B10+%2B+14+
(3) +f+%2B+10+=+s+%2B+d+%2B+34+
(3) +f+=+s+%2B+d+%2B+24+
-----------------------
Substitute (1) and (2) into (3)
(3) +6d+-+1+=+d+%2B+3+%2B+d+%2B+24+
(3) +6d+-+1+=+2d+%2B+27+
(3) +4d+=+28+
(3) +d+=+7+
----------------
(2) +f+=+6d+-+1+
(2) +f+=+6%2A7+-+1+
(2) +f+=+41+
--------------
(1) +s+=+d+%2B+3+
(1) +s+=+7+%2B+3+
(1) +s+=+10+
---------------
The father's age is 41
check:
(3) +f+%2B+10+=+%28+s%2B10+%29+%2B+%28+d%2B10+%29+%2B+14+
(3) +41+%2B+10+=+%28+10%2B10+%29+%2B+%28+7%2B10+%29+%2B+14+
(3) +51+=+20+%2B+17+%2B+14+
(3) +51+-+51+
OK
---------
(2) +f+%2B+1+=+6d+
(2) +41+%2B+1+=+6%2A7+
(2) +42+=+42+
OK
--------
(1) +s+=+d+%2B+3+
(1) +10+=+7+%2B+3+
(1) +10+=+10+
OK