Question 830055: A mother and her daughter total 66 years. Two years ago, the mother was 5 more than twice her daughters age. Find the mothers age now.
Found 2 solutions by stanbon, MathTherapy: Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A mother and her daughter total 66 years. Two years ago, the mother was 5 more than twice her daughters age. Find the mothers age now.
--------
Equations:
m + d = 66
m-2 = 2(d-2)+5
--------
m-2 = 2d +1
------
m -2d = 3
m + d = 66
-------------------
Subtract and solve for "d":
3d = 33
d = 11 yrs (daughter's age now)
--------
Solve for "m":
m + 11 = 66
m = 55 yrs (mother's age now)
=================
Cheers,
Stan H.
=================
Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
A mother and her daughter total 66 years. Two years ago, the mother was 5 more than twice her daughters age. Find the mothers age now.
Mother's current age: 
You can do the check!!
If you need a complete and detailed solution, let me know!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,
GENERAL MATH QUESTIONS, MATH HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE, GRE, CLEP,
and the GED, you can visit: http://asvabstudyzone.freeforums.net/.
|
|
|