SOLUTION: Ellis is one year younger than Denden. One-half of Ellis' age is three less than two-thirds of Denden's age. What are their present ages?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Ellis is one year younger than Denden. One-half of Ellis' age is three less than two-thirds of Denden's age. What are their present ages?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 825913: Ellis is one year younger than Denden. One-half of Ellis' age is three less than two-thirds of Denden's age. What are their present ages?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Let e = E's age
Let d = D's age
:
Write an equation for each statement
"Ellis is one year younger than Denden."
e = d-1
:
" One-half of Ellis' age is three less than two-thirds of Denden's age."
1%2F2e = 2%2F3d - 3
Get rid of those annoying denominators, mult by 6, resulting in:
3e = 4d - 18
Replace e with (d-1)
3(d-1) = 4d - 18
3d - 3 = 4d - 18
-3 + 18 = 4d - 3d
15 = d
D is 15 yrs old
Find E
e = 15 - 1
e = 14 yrs old
:
:
Check this in the statement:
"One-half of Ellis' age is three less than two-thirds of Denden's age.
1%2F2(14) = 2%2F3(15) - 3
7 = 10 - 3