SOLUTION: two years ago father was three times as old as his son and two years hence twice his age will be equal to five times that of his son find there present ages
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Question 825481: two years ago father was three times as old as his son and two years hence twice his age will be equal to five times that of his son find there present ages Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
x = father
y = son
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x - 2 = 3(y - 2)
2(x + 2) = 5(y + 2)
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put the system of linear equations into standard form
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x - 2 = 3y - 6
2x + 4 = 5y + 10
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x - 3y = -4
2x - 5y = 6
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copy and paste the above linear system in standard form into this matrix-method solver:
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solution:
x = father = 38
y = son = 14
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system matrix
1 -3
2 -5
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inverse of system matrix
-5 3
-2 1
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determinant of system matrix = 1
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Solve systems of linear equations up to 4-equations 4-variables:
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