SOLUTION: Bob is 25 years younger than his father and 27 years older than his son. What are their ages. The sum must total 100. Father Bob Son

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Question 813173: Bob is 25 years younger than his father and 27 years older than his son. What are their ages. The sum must total 100.
Father
Bob
Son
Found 2 solutions by erica65404, MathTherapy:
Answer by erica65404(394) About Me  (Show Source):
You can put this solution on YOUR website!
father = x
Bob = y
Son = z
x = 25 + y
y = y
z =y - 27
x + y + z = 100
%2825%2By%29+%2B+y+%2B+%28y-27%29+=+100
25+%2B+y+%2B+y+%2B+y+-+27+=100
3y+-+2+=+100
3y+=+102
y+=+34
Bob is 34. since his father is 25 years older, his father is 59. Since his son is 27 years younger, his son is 7.
34 + 59 + 7 = 100

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Bob is 25 years younger than his father and 27 years older than his son. What are their ages. The sum must total 100.
Father
Bob
Son

Let Bob's father's age be F

Then Bob's age = F - 25

Bob's son's age: F - 25 - 27, or F - 52

All ages total 100, so: F + F - 25 + F - 52 = 100

3F - 77 = 100

3F = 177

F, or Bob's father's age = 177%2F3, or highlight_green%2859%29

Bob's age: 59 - 25, or highlight_green%2834%29

Bob's son's age: 34 - 27, or highlight_green%287%29

You can do the check!!

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