SOLUTION: Mary is twice as old as Helen and Sue is twice as old as Mary. In ten years their combined ages will total 58 years. How old is each at the present time?
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Question 809319: Mary is twice as old as Helen and Sue is twice as old as Mary. In ten years their combined ages will total 58 years. How old is each at the present time?
You can put this solution on YOUR website! m = 2h
s = 2m
(m+10) + (h+10) + (s+10) = 58
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(m+10) + (h+10) + (s+10) = 58
m + h + s = 28
2h + h + 2m = 28
2h + h + 2(2h) = 28
7h = 28
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Answer:
h = 4
m = 8
s = 16
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