SOLUTION: A man has a daughter and a son. The son is three years older than the daughter is now. In ten years the man will be fourteen years older than the combined ages of his children at t

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Question 808163: A man has a daughter and a son. The son is three years older than the daughter is now. In ten years the man will be fourteen years older than the combined ages of his children at that time. What is the man's age?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
let m = man's present age
let d = daughters's
let s = son's
:
Write an equation for each statement:
:
A man has a daughter and a son.
The son is three years older than the daughter is now.
s = d+3
In ten years the man will be fourteen years older than the combined ages of his children at that time.
m + 10 = (s+10) + (d+10) + 14
m = s + d + 34 - 10
m = s + d + 24
Replace s with (d+3)
m = d + 3 + d + 24
m = 2d + 27
That's about all we can do with it, we have three unknowns and only 2 equations.