SOLUTION: A woman is Q years old while her son is P years old.The sum of their ages is equal to twice the difference of their ages. The product of their ages is 675. Write down the equation

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Question 799883: A woman is Q years old while her son is P years old.The sum of their ages is equal to twice the difference of their ages. The product of their ages is 675. Write down the equations connecting their ages and solve the equations connecting the ages of the woman and her son




























Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A woman is Q years old while her son is P years old.
The sum of their ages is equal to twice the difference of their ages.
Q + P = 2(Q - P))
Q + P = 2Q - 2P
P + 2P = 2Q - Q
3P = Q
:
The product of their ages is 675.
Q * P = 675
Replace P with 3P
3P * P = 675
3P^2 = 675
Divide by 3
P^2 = 225
P = sqrt%28225%29
P = 15 yrs is the son
and obviously
3(15) = 45 yrs is woman
:
:
You can confirm this in both statements