Question 787709: A mother is presently four times as old as her daughter.If the sum of their ages 6 years ago was 48, find their present ages Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A mother is presently four times as old as her daughter.If the sum of their ages 6 years ago was 48, find their present ages
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Equations:
m = 4d
m-6 + d-6 = 48
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Substitute for "m" and solve for "d":
4d-6 + d-6 = 48
5d - 12 = 48
5d = 60
d = 12 years (daughter's age now)
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Solve for "m":
m = 4d
m = 4*12 = 48 (mom's age now)
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Cheers,
Stan H.
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