SOLUTION: Let the daughter's age be x
Let the father's age be 4x
3 years ago: Daughter's age = x-3
Father's age = 4x-3
Product of their ages:( x-3)(4x-3)=430
Opening the bracket and app
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-> SOLUTION: Let the daughter's age be x
Let the father's age be 4x
3 years ago: Daughter's age = x-3
Father's age = 4x-3
Product of their ages:( x-3)(4x-3)=430
Opening the bracket and app
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Question 776905: Let the daughter's age be x
Let the father's age be 4x
3 years ago: Daughter's age = x-3
Father's age = 4x-3
Product of their ages:( x-3)(4x-3)=430
Opening the bracket and applying quadratic formula method, we shall have the roots as x= 12.3 and -8.6
So, taking the positive value of x= 12.3years.
Present ages:
Daughter's (x-3)years = 12.3-3 =9.30years (9 years 3 months)
Father's age: (4x-3)years= 4×12.3-3 = 46.21years (46 years 2 months 1day)
Checking:
9.30×46.21= 429.753 = 430 (approximated) Found 4 solutions by psbhowmick, MathTherapy, Alan3354, sciencetechnologyproductex@yahoo.co.uk:Answer by psbhowmick(878) (Show Source):
You can put this solution on YOUR website! 3 years ago a father was 4 times as old as his daughter is now. The product of their ages is 430. Calculate their present ages.
Let daughter's, and father's current ages be D, and F, respectively
Then: F - 3 = 4D ----- F = 4D + 3 ----- eq (i)
Also FD = 430 ------ eq (ii)
D(4D + 3) = 430 ----- Substituting for F in eq (ii)
Solve this to get daughter's age. Then find father's:
You should get:
Daughter's current age:
Father's current age:
You can do the check!!
Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
You can put this solution on YOUR website! 3 years ago a father was 4 times as old as his daughter is now. The product of their ages is 430. Calculate their present ages.
---------------
F*D = 430
F-3 = 4(D-3)
F = 4D - 9
----
D*(4D-9) = 430
4D^2 - 9D - 430 = 0
You can put this solution on YOUR website! Let the daughter's age be x
Let the father's age be 4x
3 years ago: Daughter's age = x-3
Father's age = 4x-3
Product of their ages:( x-3)(4x-3)=430
Opening the bracket and applying quadratic formula method, we shall have the roots as x= 12.3 and -8.6
So, taking the positive value of x= 12.3years.
Present ages:
Daughter's (x-3)years = 12.3-3 =9.30years (9 years 3 months)
Father's age: (4x-3)years= 4×12.3-3 = 46.21years (46 years 2 months 1 week)
Checking:
9.30×46.21= 429.753 = 430 (approximated