SOLUTION: Please help. Robert is five years younger than twice Steven's age. Twice Robert's age five years ago is four more than Steven's age in three years. What are their present ages

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Question 773301: Please help.
Robert is five years younger than twice Steven's age. Twice Robert's age five years ago is four more than Steven's age in three years. What are their present ages.?

Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
Let Steven's age be x
Then Robert's age is (2*x - 5)
Analyse the second statement step by step, and form the algebraic expression for
each:

1) Robert's age 5 years ago = current age - 5 = 2*x - 5 - 5 = 2*x - 10
2) Twice Robert's age 5 years ago = 2*(2*x - 10) = 4*x - 20
3) Steven's age in 3 years = x + 3
4) So, 4 more than Steven's age in 3 years = x + 3 + 4 = x + 7
The above 2 are given to be equal. So the equation is
4%2Ax+-+20+=+x+%2B+7
Simplifying
3%2Ax+=+27 or x+=+9
Steven's age = highlight%289%29
Robert's age = 2*x - 5 = 18 - 5 = highlight%2813%29
Hope you got it :)