Question 765908: A man is four time as old as his som the different between their ages is 36 years. Find the sum of their ages.
Answer by suruman(21)   (Show Source):
You can put this solution on YOUR website! Let age of son be S.
Since the man is four times as old the age of his son, his age =4*S
Difference between their age is 36 years.
Therefore,
4*S - S = 36
3*S=36
S=12, that is, age of son is 12 years.
Age of the man = 4*S = 4*12 = 48.
Sum of their ages = 48 + 12 = 60.
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