Question 760616: A man is 3 times as old as his daughter, 8 years ago the product of their ages is 112, find their present ages Found 2 solutions by unlockmath, tommyt3rd:Answer by unlockmath(1688) (Show Source):
You can put this solution on YOUR website! Hello,
Good problem.
Setting up the 2 equations correctly is the key. Let "m" represent man and "d" for daughter:
m=3d
(m-8)(d-8)=112
Substitute to get:
(3d-8)(d-8)=112
Expand out to:
3d^2-32d+64=112
Rewritten as:
3d^2-32d-48=0
Use quadratic Formula and we get:
d=12
So the father is 36 years old.
Make sense?
RJ
www.math-unlock.com
