SOLUTION: Ben and Bob are brothers. Seven years ago Bob was twice as old as Ben. In fourteen years, Ben will be 4/5th the age of Bob. How old are Ben and Bob now?

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Question 728956: Ben and Bob are brothers. Seven years ago Bob was twice as old as Ben. In fourteen years, Ben will be 4/5th the age of Bob. How old are Ben and Bob now?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = Bob's age now
Let +y+ = Ben's age now
+x+-+7+ = Bob's age 7 yrs ago
+y+-+7+ = Ben's age 7 yrs ago
+x+%2B+14+ = Bob's age in 14 yrs
+y+%2B+14+ = Ben's age in 14 yrs
-----------------------------
given:
(1) +x+-+7+=+2%2A%28+y+-+7+%29+
(2) +y+%2B+14+=+%284%2F5%29%2A%28+x+%2B+14+%29+
----------------------------
(1) +x+-+7+=+2y+-+14+
(1) +x+-+2y+=+-7+
and
(2) +5%2A%28+y+%2B+14+%29+=+4%2A%28+x+%2B+14+%29+
(2) +5y+%2B+70+=+4x+%2B+56+
(2) +4x+-+5y+=+14+
-------------------
Multiply both sides of (1) by +-4+
and add the equations
(1) +-4x+%2B+8y+=+28+
(2) +4x+-+5y+=+14+
+3y+=+42+
+y+=+14+
and
(1) +x+-+2y+=+-7+
(1) +x+-+2%2A14+=+-7+
(1) +x+=+28+-+7+
(1) +x+=+21+
--------------
Bob is 21 and Ben is 14
check:
(2) +y+%2B+14+=+%284%2F5%29%2A%28+x+%2B+14+%29+
(2) +14+%2B+14+=+%284%2F5%29%2A%28+21+%2B+14+%29+
(2) +28+=+%284%2F5%29%2A35+
(2) +28+=+28+
and
(1) +x+-+7+=+2%2A%28+y+-+7+%29+
(1) +21+-+7+=+2%2A%28+14+-+7+%29+
(1) +14+=+2%2A7+
(1) +14+=+14+
OK