SOLUTION: Plz here is my question:
The sum of the ages of a mother and her daughter are 44,3 years ago the product of their age was 192. How old is d daughter now?
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The sum of the ages of a mother and her daughter are 44,3 years ago the product of their age was 192. How old is d daughter now?
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Question 709318: Plz here is my question:
The sum of the ages of a mother and her daughter are 44,3 years ago the product of their age was 192. How old is d daughter now? Found 2 solutions by nerdybill, josmiceli:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! The sum of the ages of a mother and her daughter are 44,3 years ago the product of their age was 192. How old is d daughter now?
Let d = daughter's age
and m = mom's age
.
from:"The sum of the ages of a mother and her daughter are 44"
d+m = 44
so,
m = 44-d
.
from:"3 years ago the product of their age was 192. How old is d daughter now?"
(d-3)(m-3) = 192
(d-3)(44-d-3) = 192
(d-3)(-d+41) = 192
-d^2+41d+3d-123 = 192
-d^2+44d-123 = 192
-d^2+44d-315 = 0
d^2-44d+315 = 0
d^2-9d-35d+315 = 0
(d^2-9d)-(35d-315) = 0
d(d-9)-35(d-9) = 0
(d-9)(d-35) = 0
d = {9,35}
The daughter is 9 years old
You can put this solution on YOUR website! Let = age of Mother 3 years ago
Let = age of Daughter 3 years ago = mother's age now = Daughter's age now
given:
(1)
(2)
------------------
(1)
(1)
(1)
and
(2)
(2)
(2)
(2)
(2)
(2)
(2)
(2)
Take the square root of both sides
(2)
(2)
and, since
(1)
(1)
(1)
-------------
This didn't work because the Daughter is 32 ( 3 yrs ago )
and the Mother is 6 ( 3 yrs ago ). To make it right, just take the
negative square root of a few steps aback
(2)
(2)
(2)
(2)
Now it works out- the Daughter was 6 three years ago,
so now the Daughter is 9 now.
check answer:
(2)
(2)
(2)
OK
