Question 698744: The age of a father is five times the age of his son. After 13 years, the father's age will exceed twice that of his son by 8. How old was the father when his son was born?
Answer by vidya p(12)   (Show Source):
You can put this solution on YOUR website! Solution:
Let, son's age be 'x'.
So, Father's present age is 5x.
Now, by the question, after 15 years, fathers, age=5x+13 and son's age =x+13 and,
father's age will exceeds twice that of his son by 8 ,
Hence we get:
5x + 13 = 2( x + 13) + 8
5x + 13 = 2x + 26 + 8
5x - 2x = 26 - 13 + 8
3x = 13 + 8
3x = 21
x = 7 years,
hence the present son's age is 7 years ,
and father age is 5(x) = 5* 7
= 35 years,
when the son was born the father's age would be :
35 - 7 = 28 years.
Thanks ,
Best regards,
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