SOLUTION: Tom is 3 years older than Mary and Jane is 5 years older than Tom. What is the average age?

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Question 693184: Tom is 3 years older than Mary and Jane is 5 years older than Tom. What is the average age?

Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source):
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Tom is 3 years older than Mary and Jane is 5 years older than Tom. What is the average age?
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Equations:
t = m+3
m = t + 5
j = t+5
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Average age = (t+m+j)/3 = (t + t-3 + t+5)/3 = (3t+3)/3 = t+1
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Cheers,
Stan H.
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Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!

Tom is 3 years older than Mary and Jane is 5 years older than Tom. What is the average age?

Let Mary's age be M
Then Tom's is: M + 3, and Jane's is: M + 3 + 5, or M + 8

Sum of their ages = M + M + 3 + M + 8, or 3M + 11

Average age = , or