SOLUTION: A mother’s age is five years greater than twice her son’s age as of the present. Fifteen years ago the mother’s age was six times her son’s age. What are the present ages of the mo
Algebra ->
Customizable Word Problem Solvers
-> Age
-> SOLUTION: A mother’s age is five years greater than twice her son’s age as of the present. Fifteen years ago the mother’s age was six times her son’s age. What are the present ages of the mo
Log On
Question 667795: A mother’s age is five years greater than twice her son’s age as of the present. Fifteen years ago the mother’s age was six times her son’s age. What are the present ages of the mother and the son ? Answer by ewatrrr(24785) (Show Source):
Hi,
A mother’s age is five years greater than twice her son’s age as of the present.
Fifteen years ago the mother’s age was six times her son’s age.
y - 15 = 6(x-15) |||
(2x+5) - 15 = 6x - 90
80 = 4x
20 = x, the son's age NOW. Mother is 45
and...Fifteen years ago...
rstuv method
1. Read the problem.
2. Select the unknown.
3. Translate into an equation:
4. Use the rules to solve.
5. Verify the result
