SOLUTION: 10 years ago, I was 14 times as old as my daughter. Now I am 4 times as old as she is.

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Question 656275: 10 years ago, I was 14 times as old as my daughter. Now I am 4 times as old as she is.
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
How old am I now?
Let +x+ = my age now
+x+-+10+ = my age 10 years ago
Let +y+ = my Daughter's age now
+y+-+10+ = my Daughter's age 10 years ago
----------
given:
(1) +x+-+10+=+14%2A%28+y+-+10+%29+
(2) +x+=+4y+
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Substitute (2) into (1)
(1) +4y+-+10+=+14%2A%28+y+-+10+%29+
(1) +4y+-+10+=+14y+-+140+
(1) +14y+-+4y+=+140+-+10+
(1) +10y+=+130+
(1) +y+=+13+
and. since
(2) +x+=+4y+
(2) +x+=+4%2A13+
(2) +x+=+52+
I am 52 now and my Daughter is 13
check:
(1) +x+-+10+=+14%2A%28+y+-+10+%29+
(1) +52+-+10+=+14%2A%28+13+-+10+%29+
(1) +42+=+14%2A3+
(1) +42+=+42+
OK

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
10 years ago, I was 14 times as old as my daughter. Now I am 4 times as old as she is.
------
Equations:
m-10 = 14(d-10)
m = 4d
---------------
Substitute for "m" and solve for "d":
4d - 10 = 14d -140
10d = 130
d = 13 (daughter's age now)
----
Solve for "m":
m = 4d
m = 4*13 = 52 (me's age now)
=============================
Cheers,
Stan H.