SOLUTION: sue lee had a garden that measured 10 feet bye 20 feet. during the next season she wanted to have twice the area in her garden so she doubled the length and doubled the width of he

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: sue lee had a garden that measured 10 feet bye 20 feet. during the next season she wanted to have twice the area in her garden so she doubled the length and doubled the width of he      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 639991: sue lee had a garden that measured 10 feet bye 20 feet. during the next season she wanted to have twice the area in her garden so she doubled the length and doubled the width of her garden. explain why you agree or disagree with sue lee's solution. use diagrams and calculations to support your answer
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The area of her present garden is
+10%2A20+=+200+ square feet
Double that area is +2%2A200+=+400+ square feet
-----------------------
If she made the garden 16 x 25, then
+16%2A25+=+400+, but if she doubled
the length and width,
+20%2A40+=+800+, which is twice what she wanted