SOLUTION: ten years ago jane wasfour times as old as mary. now jane is only twice as old as mary. determine their present ages simultaneuosly

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Question 637026: ten years ago jane wasfour times as old as mary. now jane is only twice as old as mary. determine their present ages simultaneuosly
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
ten years ago, jane agehighlight%28y%29 was four times as old as mary's age highlight%28x%29
Question states*** NOW, jane is only twice as old as mary.
y + 10 = 2(x +10) || y+=+4x
4x + 10 = 2x+ 20
2x = 10
x+=+5+, mary's age 10 years ago. jane 20 then
NOW: mary is 15 and jane is 30
and...
30+=+2%2A15