SOLUTION: Four years ago, Jaybee is three times the age of his daughter Juliana. In ten years, he will be twice her age. How old are they now?

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Question 637015: Four years ago, Jaybee is three times the age of his daughter Juliana. In ten years, he will be twice her age. How old are they now?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Four years ago, Jaybee's agehighlight%28y%29 is three times the age of his daughter Juliana's agehighlight%28x%29

 Question states***In ten years... he will be twice her age

  y + 14 = 2(x + 14)    | +y+=+3x

 3x + 14 = 2x+ 28

      x = 14, Juliana's age 4 years ago.  Father was 42 then

NOW: Juliana is 18.  Father Jaybee is 46

and...10 year from now...

   56+=+2%2A28