SOLUTION: Please help me solve this problem. Peter is Y years old. His brother David is 2 years younger. In 9 years the total of their ages will be 2 times the total of their ages now.

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Question 630454: Please help me solve this problem.
Peter is Y years old. His brother David is 2 years younger. In 9 years the total of their ages will be 2 times the total of their ages now.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+y+ = Peter's age now
+y+-+2+ = His brother David's age now
+y+%2B+9+ = Peter's age in 9 years
+y+-+2+%2B+9+ = David's age in 9 yeats
------------
given:
+y+%2B+9+%2B+y+-+2+%2B+9+=+2%2A%28+y+%2B+y+-+2+%29+
+2y+%2B+16+=+2%2A%28+2y+-+2+%29+
+2y+%2B+16+=+4y+-+4+
+2y+=+20+
+y+=+10+
+y+-+2+=+8+
Peter is 10 now and
David is 8 now