SOLUTION: 1.  A is 6 years older than B. In 5 years time their total age is 70. How old are they now?                                                                                        

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Question 622402: 1.  A is 6 years older than B. In 5 years time their total age is 70. How old are they now?                                                                                                         The answer is 33 and 27, but how do you calculate this?
Found 2 solutions by josmiceli, lenny460:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
given:
(1) +a+=+b+%2B+6+
In 5 years, A's age will be +a+%2B+5+
In 5 years, B's age will be +b+%2B+5+
so,
+a+%2B+5+%2B+b+%2B+5+=+70+
+a+%2B+b+%2B+10+=+70+
(2) +a+%2B+b+=+60+
and, from (1),
(1) +a+-+b+=+6+
Now add the equations
(1) +a+-+b+=+6+
(2) +a+%2B+b+=+60+
+2a+=+66+
+a+=+33+
and, since
(2) +a+%2B+b+=+60+
(2) +33+%2B+b+=+60+
(2) +b+=+60+-+33+
(2) +b+=+27+
A is 33
B is 27

Answer by lenny460(1073) About Me  (Show Source):
You can put this solution on YOUR website!
Let the age of A be = n + 6
Let the age of B be = n
In five years time:
A = n + 6 + 5
B = n + 5
(n + 6 + 5) + (n + 5)
n + 6 + 5 + n + 5
Combine like terms:
n + n = 2n
6 + 5 + 5 = 16
2n + 16 = 70
Subtract 16 from each side of the equation.
2n + 16 - 16 = 70 - 16
Combine like terms:
16 - 16 = 0
70 - 16 = 54
2n = 54
Divide each side by 2
2n/2 = 54/2
n = 27
n + 6 = 27 + 6 = 33
Therefore:
A is 33 years old and
B is 27 years old.