SOLUTION: The ages of three children in a family can be expressed as consecutive integers. The square of the age of the youngest child is 4 more than 8 times the age of the oldest child. Fin
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Question 613358: The ages of three children in a family can be expressed as consecutive integers. The square of the age of the youngest child is 4 more than 8 times the age of the oldest child. Find the ages of the three children. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Express the 3 consecutive integers as , , represents the agr of the youngest child
given:
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I can solve completing the square
take 1/2 of the coefficient of the term, square it,
and add it to both sides
Both sides are now perfect squares:
Take the square root of both sides
I can ignore the negative square root, since it gives me
a negative age:
The ages of the 3 children is 10, 11, and 12
check:
OK
