SOLUTION: In ten years from now, a father will be twice as old as his son. Ten years ago, he was 6 times as old. How old are they now?

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Question 597336: In ten years from now, a father will be twice as old as his son. Ten years ago, he was 6 times as old. How old are they now?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +f+ = Father's age now
Let +s+ = Son's age now
given:
(1) +f+%2B+10+=+2%2A%28+s+%2B+10+%29+
(2) +f+-+10+=+6%2A%28+s+-+10+%29+
------------------------
(1) +f+%2B+10+=+2s+%2B+20+
(1) +f+-+2s+=+10+
and
(2) +f+-+10+=+6s+-+60+
(2) +f+-+6s+=+-50+
Subtract (2) from (1)
(1) +f+-+2s+=+10+
(2) +-f+%2B+6s+=+50+
+4s+=+60+
+s+=+15+
and
(1) +f+-+2s+=+10+
(1) +f+-+2%2A15+=+10+
(1) +f+-+30+=+10+
(1) +f+=+40+
The father is 40
The Son is 15
check:
(1) +40+%2B+10+=+2%2A%28+15+%2B+10+%29+
(1) +50+=+2%2A25+
(1) +50+=+50+
(2) +40+-+10+=+6%2A%28+15+-+10+%29+
(2) +30+=+6%2A5+
(2) +30+=+30+
OK