Question 595725: Today Janet's age in years is three times her dog's age ing months, In one year, the dog's age in months will be 2 times Janet's age then, in years. Today Janet is _________ years old. Please show your work.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Today Janet's age in years is three times her dog's age in months,
In one year, the dog's age in months will be 2 times Janet's age then, in years.
:
Let j = Janet's age in years
Let d = dog's age in months
:
"Janet's age in years is three times her dog's age in months,"
j = 3d
:
"In one year, the dog's age in months will be 2 times Janet's age then, in years."
d + 12 = 2(j+1)
d + 12 = 2j + 2
d = 2j + 2 - 12
d = 2j - 10
replace j with 3d
d = 2(3d) - 10
10 = 6d - d
10 = 5d
d = 10/5
d = 2 months is the dogs age
then
j = 3(2)
j = 6 yrs is Janet's age
:
:
Check this in the statement:
"In one year, the dog's age in months will be 2 times Janet's age then, in years.
2 + 12 = 2(6+1)
14 = 2(7)
|
|
|
