SOLUTION: A man is presently 4 times the age of his son. He learned that 3 years ago he was 7 times the age of his son. How old are they now?
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Question 590969
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A man is presently 4 times the age of his son. He learned that 3 years ago he was 7 times the age of his son. How old are they now?
Answer by
alicealc(293)
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let:
Man's age = m years old
Son's age = s years old
m = 4*s
m - 3 = 7*(s - 3)
4s - 3 = 7s - 21
21 - 3 = 7s - 4s
18 = 3s
s = 18/3 s = 6
m = 4s = 4*6 = 24
So, now, the man is 24 years old, and his son is 6 years old