SOLUTION: Cecile is now four times as old as daisy . Five years ago , the sum of their two ages was 45 . How old each now?

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Question 571517: Cecile is now four times as old as daisy . Five years ago , the sum of their two ages was 45 . How old each now?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+c+ = Cecile's age now
+d+ = Daisy's age now
+c+-+5+ = Cecile's age 5 yrs ago
+d+-+5+ = Daisy's age 5 yrs ago
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given:
(1) +c+=+4d+
(2) +%28+c+-+5+%29+%2B+%28+d+-+5+%29+=+45+
Substitute (1) into (2)
(2) +4d+-+5+%2B+d+-+5+=+45+
(2) +5d+-+10+=+45+
(2) +5d+=+55+
(2) +d+=+11+
and, since
(1) +c+=+4d+
(1) +c+=+4%2A11+
(1) +c+=+44+
Cecile is 44 and Daisy is 11
check:
(2) +%28+44+-+5+%29+%2B+%28+11+-+5+%29+=+45+
(2) +39+%2B+6+=+45+
(2) +45+=+45+
OK