SOLUTION: Their were 3 brothers. The probduct of their ages is 36. the sum of their ages is equal to the age of the only sister. the 3 brothers never admit their ages but the sister always a

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Question 570552: Their were 3 brothers. The probduct of their ages is 36. the sum of their ages is equal to the age of the only sister. the 3 brothers never admit their ages but the sister always admits her own even so you need to know that the oldest brother usually wears his baseball cap backwards. How old is each broter? explain
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Their were 3 brothers. The product of their ages is 36. the sum of their ages is equal to the age of the only sister.
the 3 brothers never admit their ages but the sister always admits her own
even so you need to know that the oldest brother usually wears his baseball cap backwards.
How old is each brother? explain
:
That last sentence makes me think that perhaps the two youngest are twins, the same age.
Call the oldest brother age = a, the twin brothers age, b
:
"The product of their ages is 36."
a * b * b = 36
ab^2 = 36
b^2 = 36%2Fa
b = sqrt%2836%2Fa%29
:
There are two integer solutions to this equation where a is older than b
a=9, b=2; but a two year old probably would not worry about admitting their age
and
a=4, b=3; reasonable solutions,
The oldest is 4, the twin brothers are 3,
:
"the sum of their ages is equal to the age of the only sister."
s = a + 2b
the sister would be 10