Question 567885: a father is twice older than his son and the sum of their ages is 48.How old is each? Found 3 solutions by Alan3354, Gurajan, ikleyn:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a father is twice older than his son and the sum of their ages is 48.How old is each?
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Twice = 2 times
2 times older = 3 times as old
--> 12 & 36
You can put this solution on YOUR website! Let age of son be x years.
Age of father's be y years
Now according to ques.
x+y=48
Y=2x
So eq.becomes,
x+y=48
2x-y=0
Adding these eq.
3x=48
x=16
y=2x =2×16=32
Age of son is 16
Age of father is 32.
Ik
Let the son's age is x years.
Then the father's age is 3x years, (twice older means "three times old as") and the condition says that
x + 3x = 48.
Hence, 4x = 48 and x = = 12.
Answer. The son is 12 years old. The father is 36 years old.
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