SOLUTION: Jesse has a puppy whose age in months is half Jesse's age in years. In five years, the puppy's age in months will be five more than twice Jess'es age in years. What is the puppy's

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Jesse has a puppy whose age in months is half Jesse's age in years. In five years, the puppy's age in months will be five more than twice Jess'es age in years. What is the puppy's       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 547507: Jesse has a puppy whose age in months is half Jesse's age in years. In five years, the puppy's age in months will be five more than twice Jess'es age in years. What is the puppy's current age?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I will put all the data in terms of months
Let p = puppy's current age in months
Let j = Jesse's age in months
given:
(1) +p+=+%28+1%2F2+%29%2A%28+j%2F12+%29+
(2) +p+%2B+%285%2A12%29+=+2%2A%28j%2F12%29+%2B+5+
--------------------------
This is 2 equations and 2 unknowns,
so it's solvable
(1) +p+=+j%2F24+
(2) +12p+%2B+720+=+2j+%2B+60+
(2) +6p+%2B+360+=+j+%2B+30+
Substitute (1) into (2)
(2) 6%2A%28j%2F24%29+%2B+360+=+j+%2B+30+
(2) +j%2F4+%2B+360+=+j+%2B+30+
(2) +j+-+j%2F4+=+360+-+30+
(2) +%283%2F4%29%2Aj+=+330+
(2) +j+=+%284%2F3%29%2A330+
(2) +j+=+440+
and
(1) +p+=+j%2F24+
(1) +p+=+440%2F24+
(1) +p+=+18.333+
The puppy's age is 18 months and 10 days
---------------------------------
check:
Jesse's age in years is +440%2F12+=+36.666+
The puppy's age in months is 1/2 Jesse's age in years
---------------
In 5 years, the puppy's age in months will be
+18.333+%2B+60+=+78.333+
Twice Jesse's age in years in 5 years will be
+2%2A36.666+=+73.333+
OK