SOLUTION: The age of a person is twice the sum of the ages of his two sons and five years ago his age was thrice the sum of their ages.find his present age.
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Question 543176: The age of a person is twice the sum of the ages of his two sons and five years ago his age was thrice the sum of their ages.find his present age. Found 3 solutions by lwsshak3, ajohns, JBarnum:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! The age of a person is twice the sum of the ages of his two sons and five years ago his age was thrice the sum of their ages.find his present age.
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let x=present age of father
let y=sum of ages of two sons
..
At present:
x=2y
5 years ago:
x-5=3(y-10)
substitute 2y for x
2y-5=3y-30
y=25
x=2y=50
Ans:
Present age of father=25
You can put this solution on YOUR website! I am new to this site and am not sure if this is the right place to make a query on the answer to question 543176.
Should the final answer not be father's present age is 50? Perhaps I am missing something.
....this is correct answer but as a tutor your obligated to explain and show all your work as giving them the answer doesnt help the student learn how to solve the next problem they come accross. ~Jbarnum
You can put this solution on YOUR website! f=father a=first son b=second son this says father is 2 times the age of his two sons combined. 5 years ago means you have to subtract 5 years from the father and 2 sons this tells us both a and b are less than 25 yrs old
take this and substitute it for a in the first equation
. b will cancel out
.
to check use the other equation sub f and a
correct
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