SOLUTION: seven years ago B was twice as young as A,when A was3 years younger than B is now. How old is A now?

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Question 529992: seven years ago B was twice as young as A,when A was3 years younger than B is now. How old is A now?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = A's age now
Let b = B's age now
+a+-+7+ = A's age 7 years ago
+b+-+7+ = B's age 7 years ago
---------------------------
given:
7 years ago, A was 3 years younger than B is now
(1) +a+-+7+=+b+-+3+
7 years ago, B was twice as young as A ( half A's age )
(2) +b+-+7+=+%281%2F2%29%2A%28a+-+7%29+
---------------------
(2) +2%2A%28b+-+7%29+=+a+-+7+
(2) +2b+-+14+=+a+-+7+
(2) +a+-+2b+=+-7+
and
(1) +a+-+7+=+b+-+3+
(1) +a+-+b+=+4+
(1) +-b+=+-a+%2B+4+
(1) +b+=+a+-+4+
Substitute (1) into (2)
(2) +a+-2%2A%28a+-+4%29+=+-7+
(2) +a+-+2a+%2B+8+=+-7+
(2) +-a+=+-15+
(2) +a+=+15+
A is 15
check:
(1) +b+=+a+-+4+
(1) +b+=+15+-+4+
(1) +b+=+11+
(2) +b+-+7+=+%281%2F2%29%2A%28a+-+7%29+
(2) +11+-+7+=+%281%2F2%29%2A%2815+-+7%29+
(2) +4+=+%281%2F2%29%2A8+
(2) +4+=+4+
OK